Blog Posts on triangular load
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Resultant of Parallel Force System by on Mar 14, 2010Coplanar Parallel Force System Parallel forces can be in the same or in opposite directions. The sign of the direction can be chosen arbitrarily, meaning, taking one direction as positive makes the opposite direction negative. The complete definiti...
Solution to Problem 648 | Deflection of Cantilever Beams by on Feb 7, 2010Problem 648 For the cantilever beam loaded as shown in Fig. P-648, determine the deflection at a distance x from the support. ...
Solution to Problem 648 | Deflection of Cantilever Beams by on Feb 7, 2010Problem 648 For the cantilever beam loaded as shown in Fig. P-648, determine the deflection at a distance x from the support. ...
Solution to Problem 646 | Deflection of Cantilever Beams by on Jan 16, 2010Problem 646 For the beam shown in Fig. P-646, determine the value of I that will limit the maximum deflection to 0.50 in. Assume that E = 1.5 × 106 psi. ...
Solution to Problem 645 | Deflection of Cantilever Beams by on Jan 16, 2010Problem 645 Compute the deflection and slope at a section 3 m from the wall for the beam shown in Fig. P-645. Assume that E = 10 GPa and I = 30 × 106 mm4. ...
Solution to Problem 645 | Deflection of Cantilever Beams by on Jan 16, 2010Problem 645 Compute the deflection and slope at a section 3 m from the wall for the beam shown in Fig. P-645. Assume that E = 10 GPa and I = 30 × 106 mm4. ...
Solution to Problem 646 | Deflection of Cantilever Beams by on Jan 16, 2010Problem 646 For the beam shown in Fig. P-646, determine the value of I that will limit the maximum deflection to 0.50 in. Assume that E = 1.5 × 106 psi. ...
Solution to Problem 628 | Moment Diagrams by Parts by on Oct 14, 2009Problem 628 For the beam loaded with uniformly varying load and a couple as shown in Fig. P-628 compute the moment of area of the M diagrams between the reactions about both the left and the right reaction. ...
Solution to Problem 629 | Moment Diagrams by Parts by on Oct 14, 2009Problem 629 Solve Prob. 628 if the sense of the couple is counterclockwise instead of clockwise as shown in Fig. P-628. Solution 629 \Sigma M_{R2} = 0 10R_1 = 400 + \frac{1}{2}(6)(200)(2) R_1 = 160 \, \text{lb} \Sigma M_{R1} = 0...
Solution to Problem 628 | Moment Diagrams by Parts by on Oct 14, 2009Problem 628 For the beam loaded with uniformly varying load and a couple as shown in Fig. P-628 compute the moment of area of the M diagrams between the reactions about both the left and the right reaction. Solution 628 \Sigma M_{R2} =...
