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Mathalino.com




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Current Rank: 127 (Education)
URL: http://www.mathalino.com
Site Description: Mathalino.com is a compilation of solved problems in Engineering mathematics. It includes Forums and Blogs.
Date Joined: Sep 26, 2009

Tags: mathematics, engineering, college, university, resources


Latest Blog Posts

Example 001 | Components of a Force
on Mar 18, 2010 in 2d force components of a force vector notation x-component y-component Problem 001 Problem Determine the x and y components of the forces shown below in Fig P-001.  ...



Example 002 | Components of a Force
on Mar 18, 2010 in 2d force components of a force vector notation x-component y-component Problem 002 Compute the x and y components of each of the four forces shown in Fig. P-002.  ...



Solution to Problem 653 | Deflections in Simply Supported Beams
on Mar 16, 2010 in beam deflection maximum deflection midspan deflection moment diagram simple beam uniformly distributed load Problem 653 Compute the midspan value of EIδ for the beam shown in Fig. P-653. (Hint: Draw the M diagram by parts, starting from midspan toward the ends. Also take advantage of symmetry to note that the tangent drawn to the elastic curve at mid...



Solution to Problem 654 | Deflections in Simply Supported Beams
on Mar 16, 2010 in beam deflection moment diagram simple beam uniformly distributed load Problem 654 For the beam in Fig. P-654, find the value of EIδ at 2 ft from R2. (Hint: Draw the reference tangent to the elastic curve at R2.)  ...



Components of a Force
on Mar 15, 2010 in 2d force 3d force components of a force direction cosines x-component y-component z-component Forces acting at some angle from the the coordinate axes can be resolved into mutually perpendicular forces called components. The component of a force parallel to the x-axis is called the x-component, parallel to y-axis the y-component, and so on.



Deflections in Simply Supported Beams | Area-Moment Method
on Mar 15, 2010 in beam deflection simple beam simply supported beam The deflection δ at some point B of a simply supported beam can be obtained by the following steps:  ...



Resultant of Parallel Force System
on Mar 14, 2010 in coplanar force parallel forces rectangular load resultant space force spatial force trapezoidal load triangular load uniformly distributed load uniformly varying load Coplanar Parallel Force System Parallel forces can be in the same or in opposite directions. The sign of the direction can be chosen arbitrarily, meaning, taking one direction as positive makes the opposite direction negative. The complete definiti...



Resultant of Concurrent Force System
on Mar 13, 2010 in components of a force concurrent forces coplanar force non-concurrent forces parallel forces resultant space force spatial force Resultant of a force system is a force or a couple that will have the same effect to the body, both in translation and rotation, if all the forces are removed and replaced by the resultant.  ...



Example 6 | Plane Areas in Polar Coordinates
on Mar 10, 2010 in area by integration integration of polar area plane areas polar area polar curves Example 6 What is the area within the curve r2 = 16 cos θ?  ...



Example 5 | Plane Areas in Polar Coordinates
on Mar 10, 2010 in area by integration four-leaved rose integration of polar area plane areas polar area polar coordinates polar curves Example 5 Find the area enclosed by four-leaved rose r = a cos 2θ.  ...



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